How many liters of a 3.67 m k2so4 solution are needed to provide 57.3 g of k2so4(molar mass 174.01 g/mol)? recall that m is equivalent to mol/l.

Amount of volume needed in Litres is 0.09L

Explanation:

Given that the concentration in Mol/L =3.67M

Mass of K2SO4 = 57.3g

Molar mass of K2SO4 = 174.01g/mol

From stochiometry,

Mole = Mass/Molar mass

Mole = 57.3/174.01= 0.33mol.

Concentration in mol/L=

Mole/volume

3.67=0.33/volume

Volume= 0.33/3.67

Volume = 0.09L

Therefore the volume of K2SO4 needed is 0.09L

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answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;