Consider the following reaction.
co2(g) + hz(9) —co(g) + h2o(1)
what is being oxidized?
carbon
carbon dioxide
oxygen
hydrogen
o

Hydrogen

Explanation:

Oxidation and reduction are two types of chemical reactions known as redox reactions. (Red - reduction; ox - oxidation).

A substance is oxidized when it receives an oxygen atom from an oxidizing agent. The substance that receives oxygen is known as a reducing agent.

A substance  is reduced when it donates an oxygen atom to another atom. Thus, the substance is known as an oxidizing agent - it supplies oxygen.

In the reaction:

CO2(g) + Hz(9) —CO(g) + H2O(1)

CO₂ loses oxygen to become CO and H₂ gains oxygen to become H₂O. Thus, CO₂ is an oxidizing agent and H₂ is a reducing agent.

astronomers such as edwin hubble.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol