Determine the cell notation for the redox reaction given below. 3 cl2(g) + 2 fe(s) --> 6 cl-(aq) + 2 fe3+(aq) ) fe3+(aq) | fe(s) || cl-(aq) | cl2(g) | pt

cl2(g) | cl-(aq) | pt || fe(s) | fe3+(aq)

fe(s) | fe3+(aq) || cl2(g) | cl-(aq) | pt

cl-(aq) | cl2(g) | pt || fe3+(aq) | fe(s)

fe(s) | cl2(g) || fe3+(aq) | cl-(aq) | pt

Fe(s) | Fe3+(aq) || Cl2(g) | Cl-(aq) | Pt

Explanation:

For the given reaction -

3 Cl₂(g) + 2 Fe(s)  →  6 Cl⁻(aq) + 2 Fe³⁺(aq)  

The reaction have two halves , where there is oxidation process as well as reduction process .

Oxidation process - the process of increase in the number of oxidation state .

And ,

Reduction process - the process of reduction of the number of oxidation state .  

Hence , from the reaction ,

Oxidation process -

Fe(s) → Fe³⁺(aq)

and ,

Reduction process -

Cl₂(g) → Cl⁻(aq)

Writing the cell notation -

The oxidation half is written first and followed by the reduction process , which is separated by the salt bridge .

hence , the cell notation for the above reaction is -

Fe(s) | Fe³⁺(aq) || Cl₂(g) | Cl⁻(aq) | Pt

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