You are given a 1.00 molal solution of an unknown solute dissolved in water and told that you must determine if the solute is a strong electrolyte, a weak electrolyte, or a nonelectrolyte. on testing, you find that the freezing point of the solution is -2.05 degrees celsius. is this enough information to answer the question? the molal freezing point depression constant for water is 1.86 °c/m. o no, this is not enough information o yes, the solute is a nonelectrolyte yes, the solute is a weak electrolyte yes, the solute is a strong electrolyte

Yes, the solute is a weak electrolyte

Explanation:

Depression in freezing point is given by:

= Depression in freezing point

i= vant hoff factor = ?

= freezing point constant =

m= molality

As i for non electrolytes is 1, the given compound must be an electrolyte and a weak electrolyte as the value is only slightly greater than 1.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.

it's c. elements are placed in rows based on how may valencies electrons have.