Dissolving 5.28 g of an impure sample of calcium carbonate in hydrochloric acid produced 1.14 l of carbon dioxide at 20.0 â°c and 791 mmhg. calculate the percent by mass of calcium carbonate in the sample.

Percentage by mass of calcium carbonate in the sample is 93.58%.

Explanation:

Assumptions:

given the equation of the reaction:

from assumption:

amount carbon dioxide = amount of calcium carbonate

reacting mass ( m )  = Molar Mass ( M ) * Amount ( n )

m = 0.04938397 * 100 =  4.93839

percentage by mass of   CaC = .

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explanation:

what is the average time it took the car to travel 0.25 meters?

⇒ 2.23 seconds

what is the average time it took the car to travel 0.50 meters?

⇒ 3.13 seconds