when ethane c2h6) burns, it produces carbon dioxide and water:
2c3h5(0) +702(g) → 4co2(g) + 6h2011)
how many liters of carbon dioxide will be produced when 269 l of ethane are
burned? (one mole of any gas occupies 22.4 l under certain conditions of
temperature and pressure. assume those conditions for this question.)

538L of carbon dioxide will be produced

Explanation:

This is a classic example of combustion of an alkane.

If balanced equation is not given; this format can come in handy.

For any alkane of the type : CₙH₂ₙ₊₂ , it's combustion reaction will follow:

2CₙH₂ₙ₊₂ + (3n+1) O₂  →  (2n)CO₂ + 2(n+1) H₂O

For ethane:

2C₂H₆(g) + 7O₂(g) →  4CO₂(g) + 6H₂O(l)

Here, 2 mole of ethane gives 4 moles of CO₂.

or, of ethane gives of CO₂.

Then, 269L of ethane will give:

=

= L

= 538 L

Therefore, 538L of carbon dioxide will be produced

idk

explanation: