Consider the balanced chemical reaction below and determine the percent yield for iron if 11.2 moles of iron(iii) oxide yielded 17.4 moles of iron

fe2o3+3co> 2fe+3co2

The yield percent is 77.68%

Explanation:

1 mole of yields 2 moles of Fe.

So, 11.2 moles of Iron(III) oxide must yield 22.4 moles of Fe theoretically. This is according to the balanced equation.

Theoretical Yield = 22.4 moles of Fe

Experimental Yield = 17.4 moles of Fe

Therefore, the yield percent is 77.68%

i'm pretty sure it is letter c.) car