given the following chemical reaction:

2 o2 + ch4 co2 + 2 h2o

in the reaction of 6 moles of ch4 with excess oxygen, how many moles of water could be produced?

6
c
12.01
carbon

1
h
1.01
hydrogen

8
o
16.00
oxygen

a. 4
b. 6
c. 8
d. 12

r just means there's a number of carbon in teh chain. for example rcooh means that after x number of carbon, the chain ends with cooh.

explanation:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

that's what i got you can count the number of atoms