For the oxidation of glucose (ch 206 + 602 61,0 +6co2), how many grams of
oxygen gas will be consumed when 950 g of glucose is oxidized completely?

Mass = 1017.6 g

Explanation:

Given data:

Mass of glucose = 950 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 950 g/ 180 g/mol

Number of moles = 5.3 mol

Now we will compare the moles of oxygen and glucose.

           C₆H₁₂O₆        :              O₆

                1               :               6

                5.3          :             6×5.3 = 31.8 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 31.8 mol  ×  32 g/mol

Mass = 1017.6 g