The pressure of 1 mol of gas is decreased to 0.5 atm at 273 k. what happens to the molar volume of the gas under these conditions?

Answer : The molar volume of the gas will be, 44.82 L

Solution :

Using ideal gas equation,

where,

n = number of moles of gas  = 1 mole

P = pressure of the gas = 0.5 atm

T = temperature of the gas = 273 K

R = gas constant = 0.0821 Latm/moleK

V = volume of the gas.

Now put all the given values in the above equation, we get the molar volume of the gas.

Therefore, the molar volume of the gas will be, 44.82 L

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong