An aqueous solution of 10.03 g of catalase, an enzyme found in the liver, has a volume of 1.05 l at 27°c. the solution's osmotic pressure at 27°c is found to be 0.745 torr. calculate the molar mass of g/mol

Answer : The molar mass of catalase is,

Explanation :

Formula used :

where,

= osmotic pressure  = 0.745 torr = 0.000980 atm   (1 atm = 760 torr)

C = concentration

R = solution constant  = 0.0821 L.atm/mol.K

T = temperature  =

w = mass of catalase = 10.03 g

M = molar mass of catalase = ?

V = volume of solution  = 1.05 L

Now put all the given values in the above formula, we get:

Therefore, the molar mass of catalase is,

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.