Ineed the answers to all three questions pls:

8. as a sulfur atom gains electrons, its radius
a) decreases
b) increases
c) remains the same

9. which element forms an ion larger than its atom?
a) na b) ne c) ba d) br

10. which of the following particles has the smallest
radius?
a) na b) k° c) na+ d) k+

Explanation:

8) As a sulfur atom gains electrons, its radius

A) decreases

B) increases

C) remains the same

Increases

Explanation:

when an atom form ion its atomic radius changed from neutral atomic radius.

if the atom form cation its atomic radius is smaller than neutral atomic radius.

If atom form anion its anionic radius is larger than the neutral atomic radius.

The reason is that when electron is remove energy shell deduced so cation get smaller ionic radii while in case of anion electron is added and size increase.

when sulfur gain electrons it form anion that's why its radius increases.

9) Which element forms an ion larger than its atom?

A) Na B) Ne C) Ba D) Br

Answer;

Br

Explanation:

when an atom form ion its atomic radius changed from neutral atomic radius.

if the atom form cation its atomic radius is smaller than neutral atomic radius.

If atom form anion its anionic radius is larger than the neutral atomic radius.

The reason is that when electron is remove energy shell deduced so cation get smaller ionic radii while in case of anion electron is added and size increase.

In given list of elements sodium and barium form cation while bromine form anion.

That's why anion of bromine is larger than atom.

while neon is inert it cannot form ion.

10. Which of the following particles has the smallest

radius?

A) Na B) K° C) Na+ D) K+

Na⁺

Explanation:

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased .

Sodium and potassium are present in group one. Sodium is present in period three while potassium is present in period four. So atomic size of sodium is smaller and when it form the cation its cation is smaller than its atom because of losing of electron.The reason is that when electron is remove energy shell deduced so cation get smaller ionic radii

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.