A17.55 ml solution of potassium nitrate (kno3) was diluted to 125.0 ml, and 25.00 ml of this solution was then diluted to 1.000 × 103 ml. the concentration of the final solution is 0.00383 m. calculate the concentration of the original solution.

Explanation:

Given data:

V1 = 25.0 ml

M2 = 0.00383 M

V2 = 1000 ml

we knwo that

    ∴

               = 0.1532 M

0.1532 M is concentration in 25 ml but taken from 125 ml solution.

  ∴ The concentration in 125.0 ml solution is = 0.1532 M

M1 = 0.1532 M

V1 = 125.0ml and          V2 = 17.5.0ml

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

personal, she chose to do it.