Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°c. (the equation is balanced.) pb(s) + br2(l) → pb2+(aq) + 2br(aq) pb2+(aq) + 2 e → pb(s) e° = -0.13 v br2(l) + 2 e → 2 br(aq) e° = +1.07 v

1.20 V

Explanation:

Here Pb undergoes oxidation by loss of electrons, thus act as anode. Bromine undergoes reduction by gain of electrons and thus act as cathode.

Where both are standard reduction potentials.

Given,

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