Which of the following formulas represent valid ionic compounds that can be made from these six elements: al, be, f, li, n, and s? select all that apply

a. aln
b. bes
c. alli
d. lif

Option(b) and(d)

BeS and LiF

Explanation:

Ionic compounds as the name says are the compounds which are composed of ions mainly anions and cations through the indigenous forces like Dispersion/VanderWall forces. Here the compounds being formed are Lithium Fluoride,Aluminium Nitride and Beryllium Sulfide. Now as we know the key rule to sustain as an ionic compound is the combining of metal and non metal or we can say metal- non metal bond.

Therefore berrylium being a metal and sulphide(sulphur) being a non metal forms a ionic compound ,similarly Lithium being a a metal and Florine being a non metal forms ionic compounds and so is aluminium nitride where aluminium is the metal and nitride(nitrogen) is the non metal. Whereas compound like AlLi cant form a compound because aluminium and lithium both are metals.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2