23) b is a weak base. which equilibrium corresponds to the equilibrium constant ka for hb+? a) hb+ (aq) + h2o (l) ⇌ b (aq) + h3o+(aq)b) hb+ (aq) + h3o+(aq) ⇌ h2b2+ (aq) + h2o (l)c) b (aq) + h2o(l) ⇌ hb+ (aq) + oh-(aq)d) hb+ (aq) + oh-(aq) ⇌ b (aq) + h2o (l)e) b (aq) + h3o+(aq) ⇌ hb+ (aq) + h2o (l)

The correct option is: A) HB⁺ (aq) + H₂O (l) ⇌ B (aq) + H₃O⁺ (aq)

Explanation:

The acid dissociation constant (Kₐ) is the equilibrium constant of a given dissociation reaction of an acid. It is also called the acidity constant as it represents the acidic strength of a given species.

The dissociation of a given acid (HA) gives the conjugate base (A⁻) and the hydrogen ion (H⁺).

HA + H₂O ⇌ A⁻ + H₃O⁺

The acid dissociation constant:

Whereas, the dissociation of the conjugate base (BH⁺) of a given weak base (B), gives the base (B) and the hydrogen ion (H⁺).

BH⁺ + H₂O ⇌ B + H₃O⁺

The acid dissociation constant:

i think it's c. i'm not sure but i think so.

the answer is true. hope it .