An evacuated steel vessel with a volume of 10.00 liters is filled with 32.00 atm ofpure o2 at 25°c. an electric discharge is passed through the vessel, causing someof the oxygen to be converted into ozone. as a result, the pressure inside thevessel drops to 30.64 atm at 25°c. calculate the final percent by mass of ozonein the vessel

The final mass percent of ozone in the vessel is 12.75%.

Explanation:

The chemical reaction of formation of ozone from oxygen is as follows

  (Here, molar mass of oxygen molecule = 32 g/mol)

From the given, at the end of the total pressure

 = 30.64

The gas filled with 32.00 atm.

Substitute the "x' value then we get the pressure of each gas.

Let's calculate the weight of the each gas.

rearrange the equation is as follows.

Substitute the each given value in the equation(1)

Molar mass of oxygen = 31.9988 g/mol

Temperature =

Mass % of Ozone:

Therefore,Final percent by mass of ozone in the vessel is 12.75%.

catya that's not even a b or c