Assume that the enthalpy of fusion of ice is 6020 j/mol and does not vary appreciably over the temperature range 270–290 k. if 1.40 mol of ice at 0°c is melted by heat supplied from surroundings at 284 k, what is the entropy change in the surroundings in j/k

29.7 J/K

Explanation:

To solve this problem we can use the equation

Where ΔS is the entropy change, Δq is the heat change, and T is the temperature.

We put the data given by the problem and solve for ΔS:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

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