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Chemistry, 26.11.2019 23:31 vultuxx

Ch4(g)+2o2(g)⇄co2(g)+2h2o(g) δh°rxn=−803kj/molrxn δs°rxn=−5j/(molrxn⋅k) the chemical equation above represents the exothermic reaction of ch4(g) with o2(g). which of the following best to explain why the reaction is thermodynamically favored (δg< 0) at 2000k and 1atm?

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Ch4(g)+2o2(g)⇄co2(g)+2h2o(g) δh°rxn=−803kj/molrxn δs°rxn=−5j/(molrxn⋅k) the chemical equation above...
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