A14.0 l sample of fluorine gas has a pressure of 29.0 atm at a certain temperature. at the same temperature, what volume would this gas occupy at a pressure of 2.90 atm? assume ideal behavior. v=

The volume occupied by the gas at a pressure of 2.90 atm = 140L

Explanation:

Since we are assuming ideal behavior, the gas equation is:

pV = nRT

where, p is the pressure

           V is the volume

           R is the universal gas constant

            T is the temperature

The temperature is constant. We can use the Boyle's Law:

-----(1)

atm

atm

=

Therefore, at the same temperature, the volume occupied by the gas at a pressure of 2.90 atm is 140L.

thats how its supposed to be