What is the limiting reactant if 4.0 g of nh3 react with 8.0 g of oxygen?

Answer : The limiting reagent is .

Solution : Given,

Mass of = 4.0 g

Mass of = 8.0 g

Molar mass of = 17 g/mole

Molar mass of = 32 g/mole

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 5 mole of react with 4 mole of

So, 0.25 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is .

idk i’m struggling too

the answer would be c