When 40.0 g of copper are reacted with silver nitrate solution cu + 2 agno3 --> cu(no3)2 + 2 ag 118 g of silver are obtained. what is the percent yield of silver? molar mass of silver = 107.9 g, molar mass of copper = 63.55 g

The percent yield of silver is 86.96 %

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of copper = 40.0 g

Molar mass of copper = 63.55 g/mol

Putting values in equation 1, we get:

The given chemical equation follows:

By Stoichiometry of the reaction:

1 mole of copper produces 2 moles of silver

So, 0.629 moles of copper will produce = of silver

Now, calculating the mass of silver from equation 1, we get:

Molar mass of silver = 107.9 g/mol

Moles of silver = 1.258 moles

Putting values in equation 1, we get:

To calculate the percentage yield of silver, we use the equation:

Experimental yield of silver = 118 g

Theoretical yield of silver = 135.7 g

Putting values in above equation, we get:

Hence, the percent yield of silver is 86.96 %

it's all four options.