Kemmi major does some experimental work on the combustion of sucrose: c12h22o11(s) 12 o2(g) → 12 co2(g) 11 h2o(g) she burns a 0.05392 g pellet of sucrose in a bomb calorimeter with excess oxygen. she determines the qrxn to be –916.6 j for the reaction. calculate the ∆h value for the combustion reaction. (round the answer to 3 significant digits, units of kj, pay attention to positive or negative.

Explanation:

Heat of combustion is the amount of heat released when 1 mole of the compound is completely burnt in the presence of oxygen.

To calculate the moles, we use the equation:

Thus of sucrose releases =  916.6 J of heat

1 mole of sucrose releases = of heat

Thus ∆H value for the combustion reaction is

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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