Calculate the specific heat of a piece of wood if 1500 grams of the wood absorbs
67,500 joules of heat and its temperature changes from 32 °c to 57 °c.
0.18 j/g °c
1.2 j/g °c
1.8 j/g °c
0.48 j/g °c

Specific heat capacity of wood =  1.8 j/g. °C

Explanation:

Given data:

Mass of wood = 1500 g

Heat absorbed = 67500 j

Initial temperature = 32 °C

Final temperature = 57 °C

Specific heat capacity = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = 57 - 32°C = 25°C

Q = m.c. ΔT

67500 j = 1500 g × c × 25°C

67500 j = 37500 g. °C × c

67500 j / 37500 g. °C = c

c =  1.8 j/g. °C

Specific heat capacity of wood  is  1.8 j/g. °C.

it's filtration, but this is an assumption so my apologies if i got this