You have a 5-liter container with 2.00 x 1023 molecules of ammonia gas (nh3) at stp. how many molecules of argon gas (ar) are in an identical container at the same temperature and pressure?

a. 6.02 x 1024 molecules
b. 1.30 x 1024 molecules
c. 2.00 x 1023 molecules
d. 6.02 1023 molecules

C. 2.00 x 1023 molecules

Explanation:

Given , the pressure , volume and temperature are same in both cases.

From the ideal gas equation,

                          P V = n R T

where n= no. of moles = given weight ÷ atomic weight

And 6.023 x 10^23 molecules of ammonia(NH3), weigh 17g ( 14 + 3(1 ))

So we have

P V = ((2.00 x 10^23)/(6.023 x 10^23)) x R T

Similarly, say n molecules of argon gas (Ar) are in an identical container.

So the gas equation would be

P V = ( n / 6.023 x 10^23 ) x R T

Because, atomic weight of Argon is beared by 6.023 x 10^23 molecules.

dividing these two equations, we get

n = 2.00 x 10^23 molecules

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72