Calculate the ph of a buffer solution made from 0.10 m nh3 and 0.10 m nh4cl
salt. kb = 1.8 x 10-5

b. calculate the ph of the buffer in part a, after 12 ml of 0.20 m hcl is added to 125 ml
of the buffer in part a.

c. calculate the ph when 12 ml of 0.20 m hcl added to 125 ml of water. how does
the ph compare to the ph found in part b?

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o