If six moles of oxygen gas react in excess hydrogen gas, how many grams of h2o will the reaction produce? (remember to balance the equation first.)

216 g H2O

Explanation:

O2   +  2H2 ---> 2H2O

1 mol                   2 mol

6 mol                   x mol

x mol H2O = 6 mol O2 * 2 mol H2O/1 mol O2 = 12 mol H2O

M(H2O) = 2*1.0 + 16.0 = 18.0 g/mol

12 mol H2O *(18.0 g/1 mol) = 216 g H2O

dynamic equilibrium is the answer.

i'm pretty sure it is letter c.) car