Agas turbine power plant receives a shipment of hydrocarbon fuel whose composition is uncertain but may be represented by the expression cxhy. the fuel is burned with excess air. an analysis of the product gas gives the following results on a moisture-free basis: 9.80% (v/v) co2, 5.1% o2, and 85.1% n2. collapse question part fuel composition determine the molar ratio of hydrogen to carbon in the fuel r = y/x, and the percentage excess air used in the combustion.

See explanation..

Explanation:

Equation of reaction;

CxHy + x+y/4(O2 +3.76N2) >xCO2 + y/2 H20 + ( x +y/4 ) O2 + 3.76 ( x + y/4 ) N2

One metre cube(m^3)of CxHy burnt requires = 4.76 ( x+ y/4 ) of air.

The combustion products formed ; yCO2 = x / 4.76 ( x +y/4 ) +y/4 10.5 /100

= x/ 4.76 ( x + y/4 ) +y/4 0.105 ×4.76 ( x + y/4 ) +y/4.

= x 0.5 x + 0.125 y + y/4

Multiply it by 4 -2x+0, we have;

5y + y = 4x 1.5y = 2x

molar ratio of hydrogen/ carbon,r= y/x= 2/1.5= 1.34.

For yN2 = 84.2 /100 = 3.76 ( x +y/4 ) / 4.76 (x +y/4 ) + y/4

For yO2

= 5.3 /100

= x+ y/4 / 4.76 x + 4.76 y/4 +y/4 0.053

= x +y/4 / 4.76x + 5.76 y/4 0.053( 4.76 x + 5.76y/4 )

= x+y/4 1.2 x + 0.07632 y

= x + 0.25 y 0.2 x

= 0.25 y - 0.07632 y

x = 0.174y/ 0.2= 0.87 y

y/x = 1/0.87 = 1.33

Therefore,

CxHy = C2H2 +3 (O2+3.76 N2 ) >2CO2 + O + H2O + 3.76N2

1 m^3+ 3m^3 O2 of oxygen= 2 m^3 + 1 m^3 O2

= 3 × 4.76 = 14.76 m^3

The air required = 14.28 m^3

CO2 - 10.5 m^3 O2 = 5.3 m3, N2 = 84.2 m3 ,O2 = 84.2 /3,76 = 22.3

chemical energy is stored in the chemical bonds of atoms and molecules. it can only be seen when it is released in a chemical reaction. when chemical energy is released, the substance from which the energy came is often changed into an entirely different substance.

this chemical reaction releases energy in the form of light and heat. chemical energy is the potential energy stored in the arrangement of atoms within molecules. breaking chemical bonds requires energy, while forming new chemical bonds releases energy.

the atp molecule can store energy in the form of a high energy phosphate bond joining the terminal phosphate group to the rest of the molecule. in this form,energy can be stored at one location, then moved from one part of the cell to another, where it can be released to drive other biochemical reactions.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: