A15.00 ml sample of an unknown hclo4 solution requires titration with 25.64 ml of 0.2000 m naoh to reach equivalence point. what is the concentration (molarity) of the unknown hclo4 solution

V₁ = 0.342 M

Explanation:

Given data:

Volume of HClO₄ = 15.00 mL

Volume of NaOH = 25.64 mL

Molarity of NaOH = 0.2000 M

Molarity of HClO₄ = ?

Solution:

Formula:

M₁V₁ = M₂V₂

V₁ = M₂V₂ /M₁

V₁ = 0.2000 M ×25.64 mL /15.00 mL

V₁ = 5.128 M. mL /15.00 mL

V₁ = 0.342 M

i believe it is a.) released into

explanation:

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.