Ammonia reacts with oxygen according to the equation 4n h 3 (g)+5 o 2 (g)→4no(g)+6 h 2 o(g),δ h rxn =−906 kj calculate the heat (in kj ) associated with the complete reaction of 155 g of n h 3 .

-2.07 × 10³ kJ

Explanation:

Let's consider the following balanced equation.

4 NH₃(g) + 5O₂(g) → 4 NO(g) + 6H₂O(g)    ΔHrxn =−906 kJ

The enthalpy of reaction is -906 kJ, that is, 906 kJ are released upon the reaction of 4 moles of NH₃. Taking into account that the molar mass of NH₃ is 17.0 g/mol, the heat associated with the complete reaction of 155 g of NH₃ is: