An aqueous solution is prepared by dissolving 15.6 g of cu(no3)2 ⋅ 6 h2o in water and diluting to 345 ml of solution. what is the molarity of the no3- ion in this solution?

a. 0.417 m
b. 0.121 m
c. 0.306 m
d. 0563 m
e. 0.834 m

The molarity of ions in the solution is 0.306 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Mass of solute = 15.6 g

Molar mass of = 295.6 g/mol

Volume of solution = 345 mL

Putting values in above equation, we get:

As, 1 mole of produces 1 mole of copper (II) ions and 2 moles of nitrate ions.

So, molarity of ions = (2 × 0.153) = 0.306 M

Hence, the molarity of ions in the solution is 0.306 M

the formula would be mgso4

mgso[subscript]4