Achemistry student adds a quantity of an unknown solid compound x to 5.00 l of distilled water at 15.° c . after 10 minutes of stirring, only a little x has dissolved. the student then drains off the solution and evaporates the water under vacuum. a precipitate is left behind. the student washes, dries and weighs the precipitate. it weighs 0.17 kg.
can you calculate the solubility of x in water at 15.° c

34 g/100 mL

Explanation:

The solubility of a compound can be expressed in g/100mL, for this we must divide the mass of the compound that dissolves in the solute by the volume of the solvent.

The solvent, in this case, is water, and that mass of the solute X that dissolved is the mass that was recovered after the solvent was drained and evaporated. So the solubility of X (S) is:

S = 0.17 kg/5L

S = 170g/5000mL

S = 170g/(5*1000)mL

S = 34 g/100 mL

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.