the molar heat of vaporization for water is 10.79 kj/mol. how much energy must be absorbed by 100 grams
of water at 100 °c in order to convert it to steam at 100 °c?
a 4079 0
b 140.79 k)
c 7.35 k)
d 226 kj

59.878 Kilo joules

We are given;

We are required to calculate the amount of energy absorbed to convert water to ice.

In this case;

Mass of water = 100 g

But, molar mass of water = 18.02 g/mol

Moles of water = 100 g ÷ 18.02 g/mol

                         = 5.549 Moles

Therefore;

Q = 5.549 moles × 10.79 kJ/mol

   = 59.878 Kilo joules

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.