calcium carbonate decomposes at 1200.0°c and forms carbon dioxide and calcium oxide. if 33.0 l of carbon
dioxide is collected at 1200.0° c and is then cooled to 30 °c, what is the new volume of carbon dioxide gas?

Explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law.

Data:

V₁ = 3300 L; T₁ = 1200.0 °C

V₂ = ?;          T₂ =     30    °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (1200.0 + 273.15) K = 1473.15 K

T₂ =    (30    + 273.15) K =  303.15 K

(b) Calculate the new volume

a electronegativity decreases beacuse the size of nucleus is bigger.