You order a 16 oz glass of tea (where the mass of water is 474 grams) from a local restaurant. the tea is freshly brewed and has an initial temperature of 28.29 °c. you add ice to cool it. if the heat of fusion of ice is 6.020 kj/mol and each ice cube contains exactly 1 mol of water, how many ice cubes are necessary to cool the tea to 0.41 °c? the specific heat of the "tea" is 4.184 j/g*c.

Explanation:

It is known that relation between heat energy, specific heat and temperature change is as follows.

                  Q =

where,    q = heat energy

              m = mass

              C = specific heat

          = change in temperature = =

Therefore, calculate the heat energy as follows.

               Q =

                   =

                  = 55292.06 J

or,              = 55.3 kJ        (as 1 kJ = 1000 J)

One ice cube is equal to 1 mole.

Hence, 6.020 kJ/mol of energy absorbed by 1 ice cube. And, number of ice cubes absorbing 55.3 kJ of energy will be calculated as follows.

                 = 9

Thus, we can conclude that 9  ice cubes are necessary to cool the tea to .

50.23 i believe is correct but don't quote me on that.