Ahuman lung at maximum capacity has a volume of 3.0 liters. if the partial pressure of oxygen in the air is 21.1 kilopascals and the air temperature is 295 k, how many moles of oxygen are in the lung?

a.
0.026 mol
b.
0.12 mol
c.
2.6 mol
d.
13 mol

0.026 moles

Explanation:

We are given;

Volume of the gas, V as 3.0 liters Partial pressure of the gas is 21.1 kilo-pascals or 0.208 atmTemperature is 295 K

We are required to calculate the number of moles of Oxygen

We are going to use the ideal gas equation;According to the ideal gas equation, PV = nRT, where n is the number of moles, R is the ideal gas constant 0.082057 L atm/mol.KRearranging the formula;

n = PV ÷ RT

  = (0.208 atm × 3.0 L) ÷ (0.082057 × 295 K)

  = 0.0258 moles

  = 0.026 moles

Thus, the number of moles of oxygen is 0.026 moles