A50.0 g sample of liquid water at 25.0 degree c is mixed with 29.0 g of water at 45 degree c. the final temperature of the water is degree c. the pecific heat capacity of liquid water is 4.18 j/g-k.
a) 32.3
b) 27.6
c) 102
d) 35.0
e) 142

The final temperature of the water is 88.10°C.

Given the following data:

To find the final temperature of the water:

The quantity of heat lost by the liquid water = The quantity of heat gained by the water.

Final temperature = 88.10°C

Therefore, the final temperature of the water is 88.10°C.

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The final temperature of the water will be .

The specific heat capacity formula,

As we know,

heat lost by the water = heat gained by the water

Solve the equation for x

x = 32.34

Hence, we can conclude that the final temperature of the water will be .

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

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