Ammonia (nh3) can be produced by the reaction of hydrogen gas with nitrogen gas:

3h2 + n2→2nh3

a chemist reacts 2.00 mol h2 with excess n2 . the reaction yields 0.80 mol nh3 .

what is the percent yield of the reaction? a. 25% b.40% c.60% d.80%

Percent yield = 61.5%

Explanation:

Given data:

Moles of hydrogen = 2.00 mol

Actual yield of ammonia= 0.80 mol

Percent yield = ?

Solution:

Chemical equation:

3H₂ + N₂ → 2NH₃

Now we will compare the moles of ammonia with hydrogen from balance chemical equation:

                     H₂       :       NH₃

                      3        :         2

                      2        :       2/3×2 = 1.3 mol

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 0.80 mol /1.3 mol × 100

Percent yield = 0.615 × 100

Percent yield = 61.5%