What is the molarity of zncl2 that forms when 25.0 g of zinc completely reacts with cucl2 according to the following reaction? assume a final volume of 285 ml .
zn(s)+cucl2(aq)→zncl2(aq)+cu(s)

Molarity of is 1.364 M

Explanation:

Molarity of product Zinc Chloride which is formed when 25.0 g of Zinc completely reacts with copper(II) chloride:

Firstly no of moles of Zn can be obtained from :  

, molar mass of Zn = 65.38 g/mol  

hence moles of Zn = 25.0 g / 65.38 g/mol = 0.382 mol.

Now some conversion are needed to be done like:

1 m L = 0.001 L

Volume of solution = 285 mL

Hence 285 mL = 285 × 0.001 L = 0.28 L

Finally Molarity of can be calculated by:  

Molarity of  =

Molarity = = 1.364 M.

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