Is the electrochemical cell spontaneous or not spontaneous as written at 25 ∘c ? spontaneous not spontaneous calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 ∘c . pt(s) || sn2+(0.0023 m),sn4+(0.13 m) ‖‖ fe3+(0.11 m),fe2+(0.0037 m) || pt(s) ∘sn4+/sn2+=0.154 ∘fe3+/fe2+=0.771 v

The cell potential is 0.609 V. Given E > 0 the electrochemical cell is spontaneous as written.

Explanation:

Let's consider the oxidation and reduction half-reactions and the global reaction.

Anode (oxidation): Sn²⁺(0.0023 M) ⇒ Sn⁴⁺(0.13 M) + 2 e⁻

Cathode (reduction): 2 Fe³⁺(0.11 M) + 2 e⁻ ⇒ 2 Fe²⁺(0.0037 M)

Global reaction: Sn²⁺(0.0023 M) + 2 Fe³⁺(0.11 M) ⇒ Sn⁴⁺(0.13 M) + 2 Fe²⁺(0.0037 M)

The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E° = E°red,cat - E°red,an

E° = 0.771 V - 0.154 V = 0.617 V

The Nernst equation allows us to calculate the cell potential (E) under the given conditions.

The cell potential is 0.609 V. Given E > 0 the electrochemical cell is spontaneous as written.

the answer is 303.15 or 303