Chemistry, 15.11.2019 23:31 khuak877

Consider the following metabolic reaction:
phosphoarginine + adp ? > arginine + atp
which of the following statements is true?
i) this reaction is a substrate level phosphorylation reaction
ii) this reaction is catalyzed by an isomerase
iii) this reaction is a phosphate transfer reaction
iv) this reaction is a redox reaction
v) this reaction is a coupled reaction
a) i and iii are true
b) iv and v are true
c) i, iii, and v are true
d) i, ii, iii, iv and v are all true
e) i and ii are true

Answers: 2

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Answers

Answer from: amp1955

Explanation:

* A phosphate level phosphorylation reaction is one that results in the generation of ATP.

*The reaction involves a phosphate transfer to ADP to form ATP.

*A coupled reaction in biochemistry is a form of reaction in which a form of energy is produced from another form of energy e.g. generating ATP (a higher energy compound) from ADP (a lower energy compound).

Answer from: Quest

answer : a model is often used to explain and make things easier to understand when any scientific topic needs to be demonstrated and explained.

as in this case where a scientist wants to use a model to present the results of his detailed scientific investigation. he should do it as it will him to make the audience understand the concept in a much better way. also, it can be changed according to new scientific understandings.

Answer from: Quest

Answerthis solution will not form a precipitateexplanationsolubility equilbrium: pbf₂(s) ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is $k_{sp} = [\text{pb}^{2+}][\text{f}^- ]^2 = 4 \times 10^{-8}$ (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as $q = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}}$ then, we can interpret q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product: $\begin{aligned} q & = [\text{pb}^{2+}]_{\text{initial}} \cdot [\text{f}^- ]^2_{\text{initial}} \\ & = (1.9 \times 10^{-3} ) (3.8\times 10^{3})^2 \\ & = 2.7 \times 10^{-8} \end{aligned}$ since q = 2.7 × 10⁻⁸ < ksp = 4 × 10⁻⁸, a precipitate will not form.