The concentration of a saturated bacl2 solution is 1.75 m (mol/liter) and the concentration of a saturated na2so4 solution is 2.0 m. calculate the theoretical yield, in grams, and the percent yield for your synthesis of the barium white pigment.

a) The theoretical yield is 408.45g of

b) Percent yield =

Explanation:

1. First determine the numer of moles of and .

Molarity is expressed as:

M=

- For the

M=

Therefore there are 1.75 moles of

- For the

M=}{1Lsolution}" alt="Na_{2}SO_{4}" />}{1Lsolution}" />

Therefore there are 2.0 moles of

2. Write the balanced chemical equation for the synthesis of the barium white pigment, :

3. Determine the limiting reagent.

To determine the limiting reagent divide the number of moles by the stoichiometric coefficient of each compound:

- For the :

- For the :

As the is the smalles quantity, this is the limiting reagent.

4. Calculate the mass in grams of the barium white pigment produced from the limiting reagent.

5. The percent yield for your synthesis of the barium white pigment will be calculated using the following equation:

Percent yield =

Percent yield =

The real yield is the quantity of barium white pigment you obtained in the laboratory.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

the answer is b & c i believe : )