Asample of 5.10 ml of diethylether (c2h5oc2h5; density = 0.7134 g/ml) is introduced into a 6.00 -l vessel that already contains a mixture of n2 and o2, whose partial pressures are pn2 = 0.752 atm and po2 = 0.206 atm. the temperature is held at 35.0 °c, and the diethylether totally evaporates.
a) calculate the partial pressure of the diethylether.
b) calculate the total pressure in the container.

A) partial pressure of diethylether = 0.206 atm

B) Total pressure =  1.164 atm

Explanation:

Given: Density of diethylether = 0.7134 g/mL, Volume of diethylether= 5.10 mL, Total volume = 6 L

Molar mass of diethylether = 74.12 g/mol

A) As we know, Density = given mass ÷ volume

⇒ given mass of diethylether = density × volume =  0.7134 g/mL ×5.10 mL = 3.64 g

As the number of moles of diethylether = given mass  ÷ molar mass = 3.64 g   ÷ 74.12 g/mol = 0.049 mol

To find out the pressure of diethylether, we use the ideal gas equation:

PV = nRT

Here, P is the partial pressure of the gas, n is the number of moles of gas = 0.049 mol, V is the total volume = 6 L, R is the gas constant = 0.08206 L·atm/(mol·K) and T is the temperature = 35°C = 35 + 273 = 308 K      (0 °C = 273 K)

⇒ P = nRT ÷ V  = (0.049 mol × 0.08206 L·atm/(mol·K) × 308 K) ÷ 6 L

⇒ P = 0.206 atm  = partial pressure of diethylether : pC₂H₅OC₂H₅

B) Given: partial pressure of: pN₂= 0.752 atm, pO₂ = 0.206 atm and pC₂H₅OC₂H₅ = 0.206 atm

As the Total pressure of all the gases = sum of partial pressure of the gases

⇒ Total pressure = pN2 + pO₂ + pC₂H₅OC₂H₅ = 0.752 atm +  0.206 atm 0.206 atm = 1.164 atm

Explanation:

(A)   The given data is as follows.

Volume of diethyl ether = 5.10 ml

Density of diethyl ether = 0.7134 g/ml

Partial pressure of nitrogen = 0.752 atm

Partial pressure of oxygen = 0.206 atm

Temperature = = (35 + 273) K = 308 K

As,       Density =  

           0.7134 g/ml =

                 mass = 3.63 g

Also,    No. of moles =

Hence, moles of diethyl ether will be as follows.

           No. of moles =

                                 =    

                                 = 0.0489 mol

Hence, using the ideal gas equation we will find the partial pressure of diethyl ether as follows.

                   PV = nRT

                 P = 0.206 atm

Hence, the partial pressure of diethyl ether is 0.206 atm.

(B)  As it is known that total pressure of a mixture of gases is equal to the sum of partial pressures of all the gases present in the mixture.

Therefore, we will calculate the total pressure as follows.

                     = 0.752 atm + 0.206 atm + 0.206 atm

                     = 1.164 atm

Hence, the total pressure in the container is 1.164 atm.

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.