Asolution of the primary standard potassium hydrogen phthalate (khp), khc8h4o4 , was prepared by dissolving 0.4877 g of khp in about 50 ml of water. titration of the khp solution with a koh solution of unknown concentration required 23.22 ml to reach a phenolphthalein end point. what is the concentration of the koh solution?

The concentration of KOH solution is 0.103 M.

Explanation:

To calculate the number of moles, we use the equation:

Given mass of KHP = 0.4877 g

Molar mass of KHP = 204.22 g/mol

Putting values in equation 1, we get:

The chemical reaction for the reaction of KHP with KOH follows:

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of KOH.

So, 0.0024 moles of KHP will react with = of KOH.

We are given:

Moles of KOH = 0.0024 moles

Volume of solution = 23.22 mL  = 0.02322L      (Conversion factor:  1L = 1000 mL)

Putting values in above equation, we get:

Hence, the molarity of KOH solution is 0.103 M.

може ли да зареждате повече информация, моля