Apharmaceutical chemist is working on a new large-scale synthesis for the popular pain reliever, naproxen. to be useful, however, the synthesis must be highly stereospecific, for whereas the (s) isomer of naproxen is a safe pain-reducing drug, the (r) isomer is a potentially harmful liver toxin. to determine the purity of the synthesized product, the chemist dissolves 81.6 mg of obtained product in 2.40 ml of solvent and measures the optical activity of the sample in a 5.00-cm tube, observing a value of +1.03? . a 0.500 g/ml solution of pure (s) isomer is measured under identical conditions, giving a value of + 16.5 ? .part a: continue your analysis by finding the specific rotation, [? ], of the synthesized product. express your answer in degrees. part b: determine the optical purity of the obtained product, using the calculated specific rotation values for the pure (s)-naproxen and the synthesized product. express your answer as a percentage. part c: assuming that the only impurity present in the synthesized product is the (r) enantiomer, calculate the percentage of (s)-naproxen it contains, using the previously determined value for optical purity. this can be done by adding the following two equations where d and l represent the percent quantities of the two enantiomers: d ? l = optical purityd + l = 100%

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.