Chlorine is widely used to purify municipal water supplies and to treat swimming pool water. suppose that the volume of a particular sample of cl2 gas is 8.80 l at 890 torr and 23 ∘c. how many grams of cl2 are in the sample?

Mass = 30.104 g

Explanation:

Given data:

Volume of Cl₂ = 8.80 L

Pressure = 890 torr (890/760 = 1.17 atm)

Temperature = 23°C (23+273 = 296K)

Mass of chlorine = ?

Solution:

PV = nRT

n = PV/RT

n = 1.17 atm × 8.80 L / 0.0821 atm. L. k⁻¹.mol⁻¹ × 296K

n = 10.296 atm. L / 24.30  atm. L.mol⁻¹

n = 0.424 mol

Mass of chlorine:

Mass = number of moles × molar mass

Mass = 0.424 mol  × 71 g/mol

Mass = 30.104 g

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.