In a simplified version of the solar system model (developed by niels bohr, a danish chemist), an electron resides in an excited h atom orbit with an energy of -38.42 j (initial state). if the electron drops to a second orbit (final state) with the energy -63.33 j, a photon will be emitted. what will be the energy of the photon (j)?
can someone show how to solve this problem and explain.

-24.91 J

Explanation:

Energy of emitted Photon = Energy of final state -   Energy of initial state

                                           =  -63.33  -(-38.42)

                                           =  -24.91 J

The negative sign indicates that a photon was emitted.

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

mark brainliest and have a great day!