The pressure of a tire is 200 kpa as it is pulled out from the garage on a summer
day. the temperature in the morning is 10°c. by the afternoon the temperature
of the tire in the sun has reached 28°c. what is the pressure in the tire now?

Explanation:

Gay-Lussac's law states that if P=pressure and T=temperature, then P/T=P/T. Temperature must be in Kelvin, but pressure can be in any unit.

To convert Celsius into Kelvin, just add 273: 10+273=283K, and 28+273=301K.

So using the equation,

200kPa÷283=? kPa÷301

Solving this equation gives you about 212.72 kPa.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )