Calculate the change internal energy (? e) for a system that is giving off 45.0 kj of heat and is performing 855 j of work on the surroundings.(pay attention to units! )a. 9.00 x 102 kjb. -9.00 x 102 kjc. �44.1 kjd. �45.9 kje. 44.1 kj

D. - 45.9 kJ

Explanation:

According to the first law of thermodynamics:-

Where,  

U is the internal energy

q is the heat

w is the work done

From the question,

q = - 45.0 kJ = - 45000 J ( 1 kJ = 1000 J ) (+ sign as the heat is being released)

w = 855 J (work is done on the surroundings)

So, work done by the system = - 855 J

So,

the objects have the same charge is correct.

nathan lee

5 structural isomers

the isomers are:

n-exane :   ch3ch2ch2ch2ch2ch3

2-methylpentane :   ch3ch(ch3)ch2ch2ch3

3-methylpentane :   ch3ch2ch(ch3)ch2ch3

2,3-dimethylbutane :   (ch3)2chch(ch3)2

2,2-dimethylbutane :   (ch3)3cch2ch3