How many moles of a gas will occupy 2.50l at stp

n = 0.112 mol

Explanation:

Given data:

Volume of gas = 2.50 L

Temperature = 273 K

Pressure = 1 atm

Moles of gas = ?

Solution:

PV = nRT

n = PV/RT

n = 1 atm× 2.50 L / 0.0821 atm. L. K⁻¹.mol⁻¹ . 273 K

n = 2.5 atm. L /22.4 atm. L. mol⁻¹

n = 0.112 mol

answer seismograph;

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol